2^x+1=3^(x/2)

Solution for 2^x+1=3^(x/2) equation:

2^x+1=3^(x/2)

We move all terms to the left:

2^x+1-(3^(x/2))=0

We add all the numbers together, and all the variables

2^x-(3^(+x/2))+1=0

We multiply all the terms by the denominator


2^x*2))-(3^(+x+1*2))=0

We add all the numbers together, and all the variables

2^x*2))-(3^(x+2))=0

We add all the numbers together, and all the variables

2^x*2))-(3^(x=0

Wy multiply elements

4x^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$